WebJan 25, 2024 · If the element is uniquely identified only through the classname right you can use: driver.find_element_by_class_name ("right") If both the classnames, clean and right are mandatory to identify the element, you can use css-selectors as follows: driver.find_element_by_css_selector ("li.clean.right") As an alternative you can also use …
ClassName styles not working in react - Stack Overflow
WebJul 24, 2024 · 1. If you wan't to add 'movie-card--show' on current className you can use it with classnames. import classnames from 'classnames'; Usage: className= {classnames ('Here-goes-your-classes-you-always-use', { 'movie-card--show': isHovered })} if isHovered is true it will add another class to your 'Always use classes'. Example: WebYou can bind the classnames to the styles object imported from css like below: import classNames from 'classnames/bind'; import styles from './index.css'; let cx = … snowing in the philippines
Applying React Conditional classNames Pluralsight
WebIf you don't want this behaviour to be default, in your (s)css you can use: // sCSS :local .yourClass {...} // JS import cls from '../yourCss.scss' const Component = () => ( WebMar 4, 2016 · Take a look at the classnames package. You can do stuff like this: className= {classNames ('alert', `alert-$ {type}`)} or className= {classNames ( { 'alert': true, 'alert-success': success, 'alert-error': error }) Share Improve this answer Follow answered Mar 4, 2016 at 3:17 David L. Walsh 23.8k 10 60 46 Add a comment 0 WebJun 11, 2024 · A common solution is use an isActive state property and use it to determine which class should be used. render () { const activeClassName = this.props.className + ' mycomponent-active' return ( snowing led double lantern