WebSolution Verified by Toppr Correct option is D) Since, a,b,c are in AP. ∴a=A−D,b=A,c=A+D Where, A is the first term and D is the common difference of an AP. Given, a+b+c= 23 … Web27 jun. 2024 · Explanation: a, b, c are in AP . Therefore a = b-d and c= b+d Given, a+b+c = 3/2 b= 1/2 Hence, a=1/2-d, b=1/2,c=1/2+d Given, a²,b²,c² are in GP. (b²)²= a²c² Solving the above equation, we get, (1/2-d) (1/2+d)= (±1/4) Solve for d, and we get d= 1/√2 (d≥0) a = 1/2 - 1/√2 Advertisement Still have questions? Find more answers Ask your question
If a, b, c are in A.P. and a^2, b^2, c^2 are in G.P. such that a < b ...
WebSolution: As given : a, b, c are in G.P. ⇒ b2 = ac The given expression : a2−b21 + b21 = a2−ac1 + ac1 [using b2 = ac] = a(a−c)1 + ac1 = ac(a−c)c+a−c = ac(a−c)a = ac−c21 = b2−c21 [using ac = b2 ] WebA Série A1 do Campeonato Paulista de Futebol de 2024, ou Paulistão Sicredi 2024 por motivos de patrocínio, foi a 122ª edição da principal divisão do futebol paulista. [ 2] Foi realizada e organizada pela Federação Paulista de Futebol e disputada por 16 clubes. O campeão da competição foi o Palmeiras, que chegou ao segundo título ... plymouth county teachers credit union wareham
If a1, a2, a3,... and b1, b2, b3,.... are A.P. and a1= 2, a10 = 3, a1 ...
Web18 sep. 2024 · If a2 b2 c2 are in ap then prove that a/b+c b/c+a c/a+b are in ap Advertisement Expert-Verified Answer 89 people found it helpful mailtoaditee It is given that a^2 , b^2 and c^2 are in an AP So they have a common difference b^2 - a^2 = c^2-b^2 (b - a) (b + a) = (c - b) (c + b) (b - a) / (b + c) = (c - b) / (b + a) Let; WebÐÏ à¡± á> þÿ t ¢2 í î ï ð ñ ò ó ô õ ö ÷ ø ù ú û ü Í Î Ï Ð Ñ Ò Ó Ô Õ Ö × Ø Ù Ú Û Ü ® ¯ ° ± ² ³ ´ µ ¶ · ¸ ¹ º » ¼ Ž ‘ ’ “ ” • – — ˜ ™ š › l'm'n'o' )€)0*º*»*¼*½*¾*¿*À*Á*Â*Ã*Ä*Å*Æ*Ç*È*É*š2›2œ2 2ž2Ÿ2 2ýÿÿÿ þÿÿÿ ¥9þÿÿÿ ... Web17 dec. 2014 · If a,b,c are in AP and a 2, b 2, c 2 are in HP, then prove either a = b = c or a, b, − c 2 are in GP Ask Question Asked 8 years, 3 months ago Modified 8 years, 3 months ago Viewed 8k times 5 As the title says. Although first part of the proof is obvious, I'm still able to prove it. pringles price in usa